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3x^2+9.5x-2=0
a = 3; b = 9.5; c = -2;
Δ = b2-4ac
Δ = 9.52-4·3·(-2)
Δ = 114.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.5)-\sqrt{114.25}}{2*3}=\frac{-9.5-\sqrt{114.25}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.5)+\sqrt{114.25}}{2*3}=\frac{-9.5+\sqrt{114.25}}{6} $
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